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A coin is kept at a distance 10 cm from the centre of turn table of radius 1 m just begins to slip, when the turn table rotates at speed of 90 r. p. m. Calculate the coefficient of static friction between coin and the turntable. ( g = 9.8 m/s2). |
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Answer» Given, r = 10 cm = 0.1 m radius at which it steps, Centrifugal force = Remaining static friction ⇒ μsmg = mrω2 ω = 90rpm = \(\frac{90\times 2\pi}{60}\) rad/s = 1.5 x 2π = 3π rad/s ⇒ μs x m x 9.8 = m x 0.1 x 9π2 ⇒ μs = \(\frac{0.1\times 9 \times 9.8}{9.8}\) = 0.9 |
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