A coin is placed on a turntable which is making 40 revolutions per minute. The distance of the coin from the center of the turntable is 3π2 cm. The minimum friction coefficient between the turntable and the coin is [Take g=10 m/s2]

A coin is placed on a turntable which is making 40 revolutions per min

1.	A coin is placed on a turntable which is making 40 revolutions per minute. The distance of the coin from the center of the turntable is 3π2 cm. The minimum friction coefficient between the turntable and the coin is [Take g=10 m/s2]
Answer» A coin is placed on a turntable which is making $40$ revolutions per minute. The distance of the coin from the center of the turntable is $\frac{3}{π^{2}} cm$ . The minimum friction coefficient between the turntable and the coin is [Take $g = 10 {m/s}^{2}$ ]

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A coin is placed on a turntable which is making 40 revolutions per minute. The distance of the coin from the center of the turntable is 3π2 cm. The minimum friction coefficient between the turntable and the coin is [Take g=10 m/s2]

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