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A coin is tossed 8 times. The probability of getting exactly 5 heads is -(A) \(\left(\frac{1}{2}\right)^5\)(B) \(\left(\frac{1}{2}\right)^8\)(C) \(^8C_5 \left(\frac{1}{2}\right)^8\)(D) \(^8C_5 \left(\frac{1}{2}\right)^5\) |
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Answer» Correct answer is (C) \(^8C_5 \left(\frac{1}{2}\right)^8\) |
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