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A coin is tossed ten times. The probability of getting exactly 8 heads is(A) 10C8 \((\frac{1}{2})^{10}\)(B) 10C8 \((\frac{1}{2})^{8}\)(C) \((\frac{1}{2})^8\)(D) none of these |
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Answer» Correct option is: (A) 10C8 \((\frac{1}{2})^{10}\) |
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