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A coin is tossed three times. Find the probability of getting at least 2 heads |
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Answer» `|S|=8` LET C be the event of GETTING at least 2 HEADS `thereforeC={HTH,THH,HHT,HHH}` `implies |C|=4` `therefore P(C)=|C|/|S|=4/8=1/2` |
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