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A coin is tossed three times. Find the probability of getting at most 2 heads |
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Answer» `|S|=8` Let B be the event of getting almost 2 heads `thereforeB={HT T,HTH,THH,T TH,THT, HHT, T T T}` `implies |B|=7` `therefore P(B)=|B|/|S|=7/8` |
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