1.

A coin of mass m and radius r having moment of inertia I about the axis passing through its centre and perpendicular to its plane. It is beaten uniformly to form a disc of radius 2r. What will be the moment of inertia about the same axis?

Answer»

I
2I
4 I
16 I

Solution :Moment of inertia of COIN of mass m and RADIUS r about the AXIS passing through its centre and perpendicular to its plane is
`I = (mr^2)/(2) "" … (i)`
Moment of inertia of formed disc about the same axis is `I. =(m(2r)^(2))/(2) = 4 ((mr^(2))/(2)) = 4I""` (USING (i))


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