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A coin rolls on a horizontal plane. What fraction of its total kinetic energy is rotational ? |
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Answer» Solution :TotalK.E. `=1/2mv^(2) +1/2I omega^(2), I = (MR^(2))/2, omega = V/r` `=1/2 mv^(2) + 1/2(mr^(2))/2 xx v^(2)/2 = 1/2 mv^(2) + 1/4 mv^(2)` `=3/4 mv^(2)` REQUIRED FRACTION `=(1/4 mv^(2))/(3/4 mv^(2)) =1/3` |
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