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A coin tossed twice. Find the probability of getting at least one head |
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Answer» <P> `therefore S={HH,HT,TH,T T}, |S|=4` Let B be the event of GETTING at LEAST one HEAD. `thereforeB={HT,TH, HH}implies|B|=3` `P(B)=|B|/|S|=3/4` |
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