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A coin tossed twice. Find the probability of getting at least one head

Answer»

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Answer :A coin is toss twice.
`therefore S={HH,HT,TH,T T}, |S|=4`
Let B be the event of GETTING at LEAST one HEAD.
`thereforeB={HT,TH, HH}implies|B|=3`
`P(B)=|B|/|S|=3/4`


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