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A coin tossed twice. Find the probability of getting at most one head

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Answer :A coin is TOSS twice.
`THEREFORE S={HH,HT,TH,T T}, |S|=4`
Let A be the event of GETTING exactly one HEAD.
`thereforeA={HT,TH,T T}implies|A|=3`
`P(A)=|A|/|S|=3/4`


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