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A coins is tossed three times,where E:aleast two heads,F: atmost two heads. Find P(E/F) |
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Answer» Solution :Here,S = {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT} E={HHT,HTH,THH,HHH} (because at LEAST two HEADS means two heads or three heads) F = {TTT,THT,TTH,HTT,HHT,HTH,THH} (because at the most two heads means zero head or one head or two heads) `rArr ENNF = {HHT,HTH,THH}therefore P (EnnF)=3/8 and P(F)=7/8`. Thus,P(E/F)=`(P(EnnF))/(P(F))`=3/8/7/8=3/7 |
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