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A coins is tossed three times,where E:atmost two tails, F: atleast one tail.Find P(E/F) in each case above.

Answer»

Solution :Here,S = {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
E={HHH,HHT,HTH,THH,TTH,THT,HTT}
F= {HHT,HTH,THH,HTT,THT,TTH,TTT}`rArr` `EnnF = {HHT,HTH,THH,TTH,THT,HTT} therefore `P(EnnF)`=6/8and P(E) 7/8 THUS,P(E/F)=`(P(EnnF))/(P(F))`=6/8/7/8=6/7


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