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A coins is tossed three times,where E:head on third toss,F: heads on first two tosses find P(E/F) |
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Answer» Solution :Here,S = {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT} E ={HHH,HTH,THH,TTH}, F={HHH,HHT} `ENNF={HHH}, therefor P(EnnF)=1/8 and P(F)=2/8` THUS,P(E/F) = `(P(EnnF))/(P(F))`=1/8/2/8=1/2 |
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