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A coins is tossed three times,where E:head on third toss,F: heads on first two tosses find P(E/F)

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Solution :Here,S = {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
E ={HHH,HTH,THH,TTH}, F={HHH,HHT}
`ENNF={HHH}, therefor P(EnnF)=1/8 and P(F)=2/8`
THUS,P(E/F) = `(P(EnnF))/(P(F))`=1/8/2/8=1/2


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