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A comapound in which a metal ion `M^(x+)(Z=25)` has a spin only magnetic moment of `sqrt24 `BM The number of unpaired electrons in the compound and the oxidation state of the metal ion respectively areA. 4 and 2B. 5 and 3C. 3and 2D. 4 and 3 |
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Answer» Correct Answer - A Spin only magnetic moment , `mu=sqrt(n(n+2))=sqrt24BM`or `n^(2)+2n-24=0` `implies(n+6)(n-4)=0` `therefore " "n=4" " [becausen=-6" not possible"]` Here, n is the number of unpaired electrons. Since four unpaired electrons are present, the oxidation state must be `+2`. `therefore Z+(25)=1s^(2),2s^(2),2p^(6),3s^(2)3p^(6),3d^(4)4s^(2)` |
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