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A combination of two resisters R_(1) and R_(4) are placed in an electrical circuit. In an experimental arrangement, the resistance are measured as R_(1)=(100 pm 3)Omega , R_(2)=(200 pm 4)OmegaThe equivalent resistance, when they are connected in parallel, (1)/(R_(P))=(1)/(R_(1))+(1)/(R_(2)) can be expressed as |
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Answer» `(66.7 PM 12)Omega` |
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