"A commerically available sample of sulphuric acid is 15% "H_(2)SO_(4)" by mass" ("density "= 1.10 g mL^(-1)). Calculate : Molarity Normality Molality of solution.

"A commerically available sample of sulphuric acid is 15% "H_(2)SO_(4)

1.	"A commerically available sample of sulphuric acid is 15% "H_(2)SO_(4)" by mass" ("density "= 1.10 g mL^(-1)). Calculate : Molarity Normality Molality of solution.
Answer» Solution :Calcultion of molality of solution Mass os `H_(2)SO_(4)` in solution= 15 g Mass os solvent (water) = 100-5 = 85 g Molar mass of `H_(2)SO_(4) = 98 " g mol"^(-1)` `"Molality of solution (m)"=("Mass of" H_(2)SO_(4)//"Molar mass of" H_(2)SO_(4))/("Mass of water in KG")` `=(15g//(98" g mol"^(-1)))/((85//1000 kg))=1.8 m` Step II. Calcultation of molarity of solution `"Density of solution"=1.10" g mol"^(-1)` `"Volume of 100 g of solution"=("Mass")/("Density")((100g))/((1.10" g ML"^(-1)))=90.9 mL` `"Molarity of solution (M)"=("Mass of" H_(2)SO_(4)//"Molar mass of" H_(2)SO_(4))/("Volume of solution in LITRES")` `((15g)//(98" g mol"^(-1)))/((90.9//1000 L))=1.68 M`. Step III. Calculatation of normallity of solution Normality of solution = `"Molarity "xx "Basicity"=(1.68xx2)=3.36 N`.