InterviewSolution
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InterviewSolution
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A company manufactures two models of voltage stabilizers viz., ordinary and autocut. All components of the stabilizers are purchased from outside sources, assembly and testing is carried out at company’s own works. The assembly and testing time required for the two models are 0.8 hour each for ordinary and 1.20 hours each for auto-cut. Manufacturing capacity 720 hours at present is available per week. The market for the two models has been surveyed which suggests maximum weekly sale of 600 units of ordinary and 400 units of auto-cut. Profit per unit for ordinary and auto-cut models has been estimated at Rs 100 and Rs 150 respectively. Formulate the linear programming problem. |
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Answer» (i) Variables : Let x1 and x2 denote the number of ordinary and auto-cut voltage stabilized. (ii) Objective function: Profit on x1 units of ordinary stabilizers = 100x1 Profit on x2 units of auto-cut stabilized = 150x2 Total profit = 100x1 + 150x2 Let Z = 100x1 + 150x2, which is the objective function. Since the profit is to be maximized. We have to Maximize, Z = 100x1 + 15x2 (iii) Constraints: The assembling and testing time required for x1 units of ordinary stabilizers = 0.8x1 and for x2 units of auto-cut stabilizers = 1.2x2 Since the manufacturing capacity is 720 hours per week. We get 0.8x1 + 1.2x2 ≤ 720 Maximum weekly sale of ordinary stabilizer is 600 i.e., x1 ≤ 600 Maximum weekly sales of auto-cut stabilizer is 400 i.e., x2 ≤ 400 (iv) Non-negative restrictions: Since the number of both the types of stabilizer is nonnegative, we get x1, x2 ≥ 0. Thus, the mathematical formulation of the LPP is, Maximize Z = 100x1 + 150x2 Subject to the constraints 0.8x1 + 1.2x2 ≤ 720, x1 ≤ 600, x2 ≤ 400, x1, x2 ≥ 0 |
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