InterviewSolution
Saved Bookmarks
| 1. |
A company manufactures two types of sweaters: type A and type B. It costs Rs 360 to make a type A sweater and Rs 120 to make a type B sweater. The company can make at most 300 sweaters and spend at most Rs 72000 a day. The number of sweaters of type B cannot exceed the number of sweaters of type A by more than 100. The company makes a profit of Rs 200 for each sweater of type A and Rs 120 for every sweater of type B.Formulate this problem as a LPP to maximize the profit to the company. |
|
Answer» Let’s assume x and y to be the number of sweaters of type A and type B respectively. From the question, the following constraints are: 360x + 120y ≤ 72000 ⇒ 3x + y ≤ 600 … (i) x + y ≤ 300 … (ii) x + 100 ≥ y ⇒ y ≤ x + 100 … (iii) Profit: Z = 200x + 120y Therefore, the required LPP to maximize the profit is Maximize Z = 200x + 120y subject to constrains 3x + y ≤ 600, x + y ≤ 300, y ≤ x + 100, x ≥ 0, y ≥ 0. |
|