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    				| 1. | The corner points of the feasible region determined by the following system of linear inequalities: 2x+y≤10,x+3y≤15,xy≥ 0 are (0,0) (5,0), (3,4) and (0,5)Let Z = px + qy, where p, q > 0.Condition on p and q so that the maximum of Z occurs at both (3, 4) and (0, 5) is(A) p = q (B) p = 2q (C) p = 3q (D) q = 3p | 
| Answer» The maximum value of Z is unique. ⇒ p(3) + q(4) = p(0) + q(5) | |