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A complex has empirical formula, PtCl_(2).2 NH_(3). When ground with AgNO_(3), it gives [Pt(NH_(3))_(4)(NO_(3))_(2)] and an insoluble slid Ag_(2)[PtCl_(4)] was also obtained. Name and mention the structure of the complex. |
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Answer» Solution :`2 PtCl_(2).2 NH_(3)+2 AgNO_(3)rarr[Pt(NH_(3))_(4)(NO_(3))_(2)]+Ag_(2)[PtCl_(4)]` On reaction with `AgNO_(3)`, no AgCl is formed as `Cl^(-)` ions are PRESENT as ligands in the COMPLEX `Ag_(2)[PtCl_(4)]`. Hence, the given complex must be `[PtCl_(2)(NH_(3))_(2)] or [Pt(NH_(3))_(4)][PtCl_(4)]` In the first CASE, molecular formula is same as empirical formula. IUPAC name of `[PtCl_(2)(NH_(3))_(2)]` = diammine dichloridoplatinum (II). In the second case, molecular formula is double of empirical formula. IUPAC name of `[Pt(NH_(3))_(4)][PtCl_(4)]`= tetraammine PLATINUM (II) tetraachloridoplatinate (II). |
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