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A compound `(80 g)` on analysis gave `C=24 g, H=4 g, O=32 g`. Its empirical formula isA. (a)`C_(2)H_(2)O_(2)`B. (b)`C_(2)H_(2)O`C. (c )`CH_(2)O_(2)`D. (d)`CH_(2)O` |
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Answer» Correct Answer - D `C=24 g, H=4 g, O=32 g`, So, Molecular formula `=C_(2)H_(4)O_(4)` So, Empirical formula`=CH_(2)O` (Simplest formula) |
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