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A compound [A] gives positive iodoform test in 5 minutes. When 6.0 g of [A] is treated with sodium metal, 1120 mL of hydrogen gas is evolved at `NTP`. It is assumed that [A] contains one atom of oxygen per molecule. Further when [A] reacts with `PBr_(3)`, a compound [B] is formed which on reacting with benzene in the presence of anhydrous `AlCl_(3)` gives a compound [C]. the compound [C] is a well known industrial compound and is used in the commercial preparation of phenol. The molar mass of compound [A] is :A. `60.0" g mol"^(-1)`B. `90.0" g mol"^(-1)`C. `100.0" g mol"^(-1)`D. `120.0" g mol"^(-1)` |
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Answer» Correct Answer - A The data suggests that the compound [A] is an alcohol. `underset("2 moles")(2 ROH)+2Na rarr2RONa+underset(22400 mL)(H_(2))` 22400 mL of `H_(2)` is evolved from alcohol `=2` mol 1120 mL of `H_(2)` is evolved from alcohol `=1120/22400xx2=0.1` mol. Now, 0.1 mole of `ROH=` 6g `:.` 1.0 mole of `ROH =` 60 g |
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