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A compound (A) of boron reacts with NMe_(3) togive an adduct(B) whichon hydrolysis gives a compound (C ) and hydrogengas. Compound (C )is a acid. Identify the compounds A, B and C. Givethe reactionsinvolved. |
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Answer» Solution :Since compound(A) of BORON reacts with `Nme_(3)` to forman ADDUCT (B), THEREFORE, (A) must be a Lewisacid. Since adduct (B)on hydrolysis gives an acid (C )and hydrogengas, therefore (A) must be `B_(2)H_(6)` and (C ) must be boric acid. `underset("Diborane (A)")(B_(2)H_(6)) + underset("Adduct (B)")(2NMe)rarr 2BH_(3).NMe_3, underset((B))(BH_(3).NMe_(3))+3H_(2)O rarr underset("Boric acid (C) ")(H_(3)BO_(3)) + 6H_(2) +NMe_(3)` |
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