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A compound (A) of boron reacts with NMe_(3) togive an adduct(B) whichon hydrolysis gives a compound (C ) and hydrogengas. Compound (C )is a acid. Identify the compounds A, B and C. Givethe reactionsinvolved.

Answer» <html><body><p></p>Solution :Since compound(A) of <a href="https://interviewquestions.tuteehub.com/tag/boron-400820" style="font-weight:bold;" target="_blank" title="Click to know more about BORON">BORON</a> reacts with `Nme_(3)` to forman <a href="https://interviewquestions.tuteehub.com/tag/adduct-849678" style="font-weight:bold;" target="_blank" title="Click to know more about ADDUCT">ADDUCT</a> (B), <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>, (A) must be a Lewisacid. <br/> Since adduct (B)on hydrolysis gives an acid (C )and hydrogengas, therefore (A) must be `B_(2)H_(6)` and (C ) must be boric acid. <br/> `underset("Diborane (A)")(B_(2)H_(6)) + underset("Adduct (B)")(2NMe)rarr 2BH_(3).NMe_3, underset((B))(BH_(3).NMe_(3))+3H_(2)O rarr underset("Boric acid (C) ")(H_(3)BO_(3)) + 6H_(2) +NMe_(3)`</body></html>


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