A compound C (molecular formula, C2H4O2) reacts with Na metal to form

1.	A compound C (molecular formula, C2H4O2) reacts with Na metal to form a compound R and evolves a gas that burns with a pop sound. Compound C on treatment with an alcohol A in presence of an acid forms a sweet-smelling compound S (molecular formula, C3H6O2). On addition of NaOH to C, it also gives R and water. S on treatment with NaOH solution gives back R and A. Identify C, R, A, S and write down the reactions involved.
Answer» C — Ethanoic acid R — Sodium salt of ethanoic acid (sodium acetate) and gas evolved is hydrogen A — Methanol S — Ester (Methyl acetete) (a) 2CH₃COOH + 2Na → 2CH₃COO Na + H₂ (b) \(CH_3COOH+NaOH\overset{Conc.H_2SO_4}\rightarrow CH_3COOCH_3+H_2O\) (c) CH₃COOH + NaOH → CH₃COONa + H₂O (d) CH₃COOCH₃ + NaOH → CH₃COONa + CH₃OHa

A compound C (molecular formula, C2H4O2) reacts with Na metal to form a compound R and evolves a gas that burns with a pop sound. Compound C on treatment with an alcohol A in presence of an acid forms a sweet-smelling compound S (molecular formula, C3H6O2). On addition of NaOH to C, it also gives R and water. S on treatment with NaOH solution gives back R and A. Identify C, R, A, S and write down the reactions involved.

Answer»

C — Ethanoic acid

R — Sodium salt of ethanoic acid (sodium acetate) and gas evolved is hydrogen

A — Methanol

S — Ester (Methyl acetete)

(a) 2CH₃COOH + 2Na → 2CH₃COO Na + H₂

(b) \(CH_3COOH+NaOH\overset{Conc.H_2SO_4}\rightarrow CH_3COOCH_3+H_2O\)

(c) CH₃COOH + NaOH → CH₃COONa + H₂O

(d) CH₃COOCH₃ + NaOH → CH₃COONa + CH₃OHa