A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% of chlori

1.	A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% of chlorine. Its molar mass is 98.96g. What are its empirical and molecular formulas?
Answer» Answer: Chemistry A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% chlorine. Its molar mass is 98.96g. What are its empirical and molecular formulas? December 27, 2019avatar Nizam Yaswanth SHARE ANSWER step 1 Divide the given PERCENTAGES of atoms with their molecular masses H---4.07/1 =4.07 C---24.27/12 =2.02 Cl--71.65/35.5=2.01 step 2 divide all values with the lowest VALUE obtained. H---4.07/2.01=2 C---2.02/2.01=1 Cl---2.01/2.01=1 THEREFORE the empirical formula is CH_2ClCH 2 Cl WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5 Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C_2H_4Cl_2C 2 H 4 Cl 2 .

A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% of chlorine. Its molar mass is 98.96g. What are its empirical and molecular formulas?

Answer»

Answer:

Chemistry

A compound contains 4.07% hydrogen, 24.27% carbon and 71.65% chlorine. Its molar mass is 98.96g. What are its empirical and molecular formulas?

December 27, 2019avatar

Nizam Yaswanth

ANSWER

step 1

Divide the given PERCENTAGES of atoms with their molecular masses

H---4.07/1 =4.07

C---24.27/12 =2.02

Cl--71.65/35.5=2.01

step 2

divide all values with the lowest VALUE obtained.

H---4.07/2.01=2

C---2.02/2.01=1

Cl---2.01/2.01=1

THEREFORE the empirical formula is

CH_2ClCH

WEIGHT OF EMPIRICAL FORMULA=12+2+35.5=49.5

Given molecular weight =98.96 which is double of empirical weight .therefore molecular formula is C_2H_4Cl_2C