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A compound formed by elements X and Y has a cubic structure in whch X atoms are at the corner of the cube and also at the face centers. Y atoms are present at the body center and at the edge center of the cube. If all the atoms from the diagonals of one of the face of the cube are removed, then Z_(eff) is |
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a><br/>4<br/>7<br/><a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a><br/></p>Solution :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/NAR_CHM_XII_V02_C02_E01_329_S01.png" width="80%"/> <br/> `XrArr4` corner atoms are removed <br/> `XrArr1` <a href="https://interviewquestions.tuteehub.com/tag/face-982590" style="font-weight:bold;" target="_blank" title="Click to know more about FACE">FACE</a> center atom is removed <br/> `Z_(eff(X))=(n_(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>))/(8)+(n_(f))/(2)=((8-4))/(8)+((6-1))/(2)=(1)/(2)+(5)/(2)=3`<br/> `Z_(eff(Y))=(n_(b))/(1)+(n_(f))/(4)=(1)/(1)+(12)/(4)=1+3=4` <br/> `Z_(eff(X))=3+4=7`</body></html> | |