A compound forms hexagonl close-packed structure. What is the total number of voids in 0.5 mol of its? How many of these are tetrahedral voids ?

A compound forms hexagonl close-packed structure. What is the total nu

1.	A compound forms hexagonl close-packed structure. What is the total number of voids in 0.5 mol of its? How many of these are tetrahedral voids ?
Answer» Solution :No. of ATOMS in the olose packing = 0.5 mol = ` 0.5 xx 6.022 xx 10^(23) = 3.011 xx 10^(23)` No. of OCTAHEDRAL VOIDS =No, of atoms in the packing = ` 3.011 xx 10^(23)` No. of TETRAHEDRAL voids = ` 2xx` No, of atoms in the packing = ` 2xx 3.011 xx 10^(23)= 6.022 xx 10^(23)` Total no. of voidsl `= 3.011 xx 10 + 6.022 xx 10^(23) = 9.033 xx 10^(23)`