A compound forms hexagonl close-packed structure. What is the total number of voids in 0.5 mol of its? How many of these are tetrahedral voids ?

A compound forms hexagonl close-packed structure. What is the total nu

1.	A compound forms hexagonl close-packed structure. What is the total number of voids in 0.5 mol of its? How many of these are tetrahedral voids ?
Answer» <html><body><p></p>Solution :No. of <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> in the olose packing = 0.5 mol = ` 0.5 xx 6.022 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(23) = 3.011 xx 10^(23)`<br/> No. of <a href="https://interviewquestions.tuteehub.com/tag/octahedral-1127994" style="font-weight:bold;" target="_blank" title="Click to know more about OCTAHEDRAL">OCTAHEDRAL</a> <a href="https://interviewquestions.tuteehub.com/tag/voids-1447686" style="font-weight:bold;" target="_blank" title="Click to know more about VOIDS">VOIDS</a> =No, of atoms in the packing = ` 3.011 xx 10^(23)` <br/>No. of <a href="https://interviewquestions.tuteehub.com/tag/tetrahedral-2294863" style="font-weight:bold;" target="_blank" title="Click to know more about TETRAHEDRAL">TETRAHEDRAL</a> voids = ` 2xx` No, of atoms in the packing = ` 2xx 3.011 xx 10^(23)= 6.022 xx 10^(23)`<br/>Total no. of voidsl `= 3.011 xx 10 + 6.022 xx 10^(23) = 9.033 xx 10^(23)`</body></html>