1.

A compound having the formula `Br_(3) C_(6)H_(3) (C_(3) H_(g))_(n)` contains `10.46% Br` by mass, the value of `n` isA. `54`B. `65`C. `45`D. `35`

Answer» Correct Answer - C
`% Br = (3 xx "AM of Br")/("MM of compound") xx 100%`
(AM is atomic mass, MM is molar mass)
`10.46% = (3(79.9u))/(314.7 + 44n) xx 100%`
`n = 45`


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