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A compound is analyzed and found to consist of 50.4% Ce,15.1% N and 34.5% O by mass. What is the correct formula for the compound ? (Atomic wt. of Ce = 140)A. `Ce_(2)(NO_(3))_(2)`B. `Ce_(2)(NO_(2))_(3)`C. `Ce(NO_(3))_(2)`D. `Ce(NO_(2))_(3)`

Answer» Correct Answer - D
`{:(Ce,N,O,,),((50.4)/(140),(15.1)/(14),(34.5)/(16),,"formula" Ce(NO_(2))_(3)),(0.36,1.07,2.15,,),(1" ":,3" ":,6,,):}`


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