A compound on analysis gave the following percentage composition: C = 24.47%, H= 4.07 %, Cl = 71.65%. Find out its empirical formula.

A compound on analysis gave the following percentage composition: C =

1.	A compound on analysis gave the following percentage composition: C = 24.47%, H= 4.07 %, Cl = 71.65%. Find out its empirical formula.
Answer» SOLUTION : `:.` The empirical FORMULA - `CH_(2)Cl`