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A compound on analysis gave the following percentage composition: C - 54.54%, H = 9.09%, 0 = 36.36% |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`C_2H_4O`</body></html> | |