1.

a compound with a molar mass of 544.0g/mol is made up of 26.5g of carbon, 2.94g of hydrogen 70.6g oxygen. what is it's empirical and molecular formula? ​

Answer»

tion:C H N 74 8.7 17.3 PERCENTAGE 12 1 14 Atomic Mass 6.17 8.70 1.23 Number of Moles 5.01 7.07 1 SIMPLE MOLAR ratio( ÷ by 1.23)Hence, C:H:N=5:7:1Empirical formula of nicotine is C 5 H 7 N



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