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A compound Z with molecular formula C_(3)H_(9)N reacts with C_(6)H_(5)SO_(2)Cl to give a solid, insoluble in alkali. Identify Z. |
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Answer» SOLUTION :Since the amine Z to treatment with `C_(6)H_(5)SO_(2)Cl` gives a product which is insoluble in alkali, therefore, the product does not have a replaceable HYDROGEN on the N-atom. In other words, the amine Z is a `2^(@)` amine. The only `2^(@)` amine having the M.F. `C_(3)H_(9)N` is ethylmethylamine, i.e., the amine (Z) is ethylemthylamine, `CH_(3)CH_(2)NHCH_(3)` `underset("Ethylmethylamine (Z)")(CH_(3)CH_(2)-underset(CH_(3))underset(|)(N)H)+underset("Benzenesulphonyl chloride")(C_(6)H_(5)-underset(O)underset(||)OVERSET(O)overset(||)(S)-Cl)to underset("N-Ethyl-N-methylbenzenesulphonamine")(CH_(3)CH_(2)-underset(H_(3)C)underset(|)(N)-underset(O)underset(||)overset(O)overset(||)(S)-C_(6)H_(5))` |
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