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A concave lens of glass, refractive index 1.5 has both surfaces of same radius of curvature R.On immersion ina medium of refractive index 1.75 it will behave asa lens

Answer»

Solution :When glass LENS is immersed in a MEDIUM, its refractive index `^m mu_s. ^m mu_s= ^amu_G/mu_g = 1.50/1.75=6/7`
`therefore` By lens MAKER formula
`1/f=(m mu_g-1) (1/R_1-1/R_2) or 1/f=(6/7-1)(-1/R-1/R)`
or `1/f=(-1/7) (-2/R) or f=(7R)/2=3.5 R`
Hence the given lens in medium behaves like convergent lens of FOCAL length 3.5R.


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