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A condenser has a capacity `2muF` and is charged to a voltage of 50 V. The energy stored isA. `25xx10^(5)J`B. 25 JC. `25xx10" erg"`D. `25xx10^(3)" erg"` |
Answer» Correct Answer - D Energy stored in a capacitor, `E=(1)/(2)CV^(2)` Here `C=2muF=2xx2xx10^(-6)F, V=50V` `=(1)/(2)xx2xx10^(-6)xx50xx50` `=25xx10^(-4)xx10^(7)" "(because 1J=10^(7)"erg")` `=25xx10^(3)"eqg"` |
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