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A condenser of capacity `10 mu F` is charged to a potential of `500 V`. Its terminals are then connected to those of an uncharged condenser of capacity `40 mu F`. The loss of energy in connecting them together is.A. 1 JB. `2.5 J`C. 10 JD. 12 J |
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Answer» Correct Answer - A `Delta E=(1)/(2)(C_(1)C_(2))/(C_(1)+C_(2))(V_(1)-V_(2))^(2)`. |
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