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A condenser of capacity 16mF charged to a potential of 20V is connected to a condenser kf capacity C charged to a potential of 10V as shown in the figure. If the common potential is 14V the capacity C is |
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Answer» C1= 16 mF V1= 20V V2=10V C2= C Common potential V=14v V = C1V1-C2V2/C1+C2 14= 16*20-C*10/16+C 14(16+C)= 16*20-C*10 224+14C= 320- 10C 320-224= 14C+10C 96/24 = C C= 4 mF |
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