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A condenser of capacity `C` is charged to a potential difference of `V_(1)`. The plates of the condenser are then connected to an ideal inductor of inductance `L`. The current through the inductor wehnn the potential difference across the condenser reduces to `V_(2)` isA. `(C(V_(1)^(2)-V_(2)^(2)))/(L)`B. `(C(V_(1)^(2)+V_(2)^(2)))/(L)`C. `((C(V_(1)^(2)-V_(2)^(2)))/(L))^(1//2)`D. `((C(V_(1)-V_(2))^(2))/(L))^(1//2)`

Answer» Correct Answer - C


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