InterviewSolution
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InterviewSolution
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A conducing circular loop is placed in a uniform magnetic field of indution `B` tesla with its plane normal to the field. Now, radius of the loop starts shrinking at the rate `(dr//dt)`. Then the induced e.m.f. at the instant when the radius is `r` is:A. `pirB(dr//dt)`B. `2pirB(dr//dt)`C. `pir^(2)(dB//dt)`D. `(pir^(2)//2)B(dr//dt)` |
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Answer» Correct Answer - B Induced emf, `e=B.(dS)/(dt)=2pirB.(dr)/(dt)` where, `(dr)/(dt)` is the rate at which radius of loop is shrinking. |
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