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A conducting body 1 has some initial charge Q, and its capacitance is C. There are two other caoducting bodies, 2 and 3, having capacitances :C_(2)=2C and C_(3)rarr oo. Bodies 2 and 3 are initially uncharged. ''Body 2 is touched with body 1. Then, body 2 is removed from body 1 and touched with body 3, and times. Then, the charge on body 1 at the end must be

Answer»

`Q//3^(N)`
`Q//3^(N-1)`
`Q//N^(3)`
None

Solution :When we touched first time charge on first CAPACITOR beacomes `(Q)/(3)` and on second capacitor it becomes `(2Q)/(3)` But when `2C` is touched with `C rarroo` it becomes uncharged so after first OPERATION.
`Q_(1) = (Q)/(3)`
after `II^(nd)` operation `Q_(2) = (1)/(3) ((Q)/(3)) = (Q)/(3^(2))`
so after `N^(TH)` operation `Q_(N) = (Q)/(3^(N))`


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