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A conducting ring of mass 2kg and radius `0.5m` is placed on a smooth plane. The ring carries a current of `i=4A`. A horizontal magnetic field `B=10 T` is switched on at time `t=0` as shown in fig The initial angular acceleration of the ring will be .A. `40pirad s^-2`B. `20pirad s^-2`C. `5pirad s^-2`D. `15pirad s^-2` |
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Answer» Correct Answer - a Due to torque of magnetic field, ring will rotate about vertical diameter. `tau=Ialphaimplies MB=Ialpha` `implies ipir^2B=1/2mr^2alpha` `implies alpha=(2iBpi)/m=(2xx4xx10pi)/2=40pi rads^-2` |
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