InterviewSolution
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InterviewSolution
| 1. |
A conducting square loop of side l and resistance R moves in its own plane with uniform velocity v perpendicular to one of its sides. A magnetic field H, constant in time and and space pointing perpendicular and into the plane of the loop every where. The current induced in the loop is :(a) H ⁄ v R anti-clockwise (b) H ⁄ v R clockwise(c) 2H ⁄ v R anti-clockwise (d) zero |
| Answer» <p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Correct option (d) zero</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="color:#000000"><span style="font-family:Arial,Helvetica,sans-serif">Induced e.m.f. in the loop will be zero due to the reason that the magnetic flux linked with the coil remains same and hence, induced current in the loop is zero.</span></span></p> | |