A conductivity cell has been calibrited with 0.01 M electrolyte solution (`k=1.25xx10^(-3)" S "cm^(-1)`) in the cell and the measured resistance is 800 ohms at `25^(@)C`. The cell constant will be :A. `1.02 cm^(-1)`B. `0.102 cm^(-1)`C. `1.00 cm^(-1)`D. `0.5 cm^(-1)`

A conductivity cell has been calibrited with 0.01 M electrolyte soluti

1.	A conductivity cell has been calibrited with 0.01 M electrolyte solution (`k=1.25xx10^(-3)" S "cm^(-1)`) in the cell and the measured resistance is 800 ohms at `25^(@)C`. The cell constant will be :A. `1.02 cm^(-1)`B. `0.102 cm^(-1)`C. `1.00 cm^(-1)`D. `0.5 cm^(-1)`
Answer» Correct Answer - C (c ) Specific conductance (k) `=(1)/(R )xx(1)/(a)` `(l)/(a)=kxxR` `=(1.25xx10^(-3)" ohm"^(-1)cm^(-1))xx(800" ohm")` `=1.0 cm^(-1)`

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A conductivity cell has been calibrited with 0.01 M electrolyte solution (`k=1.25xx10^(-3)" S "cm^(-1)`) in the cell and the measured resistance is 800 ohms at `25^(@)C`. The cell constant will be :A. `1.02 cm^(-1)`B. `0.102 cm^(-1)`C. `1.00 cm^(-1)`D. `0.5 cm^(-1)`

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