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A conductivity cell was filled with 0.02M solution which has a specific conductance of . If its resistance is 82.4 ohm at , the cell constant is |
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Answer» Here is your AnswerExplanation:The specific conductance (κ) is the PRODUCT of cell CONSTANT ( al ) and reciprocal of RESISTANCE ( R1 ). Hence, al =κ×R=2.768×10 −3 OHM −1 cm −1 ×82.4ohm=0.2281cm −1 . |
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