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A conductor carrying current I is of the type as shown in figure. Find the magnetic field induction at the common centre O of all the three arcs. A. `(5mu_(0)Itheta)/(24pir)`B. `(mu_(0)Itheta)/(24pir)`C. `(11mu_(0)Itheta)/(24pir)`D. zero |
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Answer» Correct Answer - A `B = B_(1)-B_(2) + B_(3)` `= (mu_(0)Itheta)/(4pir)-(mu_(0)Itheta)/(8pir) + (mu_(0)Itheta)/(12pir)` `= (mu_(0)Itheta)/(4pir) (1-(1)/(2) + (1)/(3))` `= (mu_(0)Itheta)/(4pir)((6-3+2)/(6))` `= (mu_(0)Itheta)/(4pir) xx (5)/(6)` |
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