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A conductor carrying current I is of the type as shown in figure. Find the magnetic field induction at the common centre O of all the three arcs. |
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Answer» Correct Answer - `(5mu_0Itheta)/(24pir)` We know that magnetic field induction at the centre of an arc subtending an angle `theta` is `B=(mu_0)/(4pi)I/rtheta` `:.` Total magnetic field induction at O due to current through the three arcs is `B=(mu_0)/(4pi)I[1/r-(1)/(2r)+(1)/(3r)]theta=(5mu_0Itheta)/(24pir)` |
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