1.

A conductor of capacity 20 mF is charged to 1000 V. the potential energy of the conductor will be A) 20 x 104 J B) 104 JC) 20 x 103 JD) 103 J

Answer»

The correct option is B) 104 J.

The energy stored in the capacitor will be 10 kilo-joules.

We know that energy stored in a capacitor = cV2/2 

Given that 

Capacitance = 20 mF = 20 x 10-3 

Voltage, V = 1000 v

Hence, energy = cV2/2 

= 20 x 10-3 x 10002 / 2

= 104 j

= 10 kj

Hence the energy stored in the capacitor will be 10 kilo-joules.



Discussion

No Comment Found