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A conductor of capacity 20 mF is charged to 1000 V. the potential energy of the conductor will be A) 20 x 104 J B) 104 JC) 20 x 103 JD) 103 J |
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Answer» The correct option is B) 104 J. The energy stored in the capacitor will be 10 kilo-joules. We know that energy stored in a capacitor = cV2/2 Given that Capacitance = 20 mF = 20 x 10-3 Voltage, V = 1000 v Hence, energy = cV2/2 = 20 x 10-3 x 10002 / 2 = 104 j = 10 kj Hence the energy stored in the capacitor will be 10 kilo-joules. |
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