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A conductor of length 2 m carrying current 2 A is held parallel to an infinitely long conductor carrying current of 12 A at a distance of 100 mm, the force on small conductor isA. `8.6 xx 10^(-5)N`B. `6.6 xx 10^(-5)N`C. `7.6 xx 10^(-5)N`D. `9.6 xx 10^(-5)N` |
Answer» Correct Answer - D Here, `I_(1)=2A, I_(2)=12A, r = 100mm=0.1m, l=2m` Now total force on length l of smal conductor `F=(mu_(0))/(4pi)xx(2I_(1)I_(2))/(r)l=(10^(-7)xx2xx2xx12xx2)/(0.1)=9.60xx10^(-5)N` |
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