A constant force acting on a body of mass 3.0 kg changes its speed fro

1.	A constant force acting on a body of mass 3.0 kg changes its speed from 2.0 ms-1 to 3.5 ms-1 in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?
Answer» Here, u = 2 ms^-1, v = 3.5 ms^-1, t = 25 s From v = u + at ⇒ 3.5 = 2 + a x 25 ⇒ a = {3.5 - 2}/{25} = 0.06 ms^-2 Mass of the body = m = 3 kg Force acting on the body F = ma = 3 x 0.06 = 0.18 N Since the applied force increases the speed of the body, it acts in the direction of the motion.

A constant force acting on a body of mass 3.0 kg changes its speed from 2.0 ms-1 to 3.5 ms-1 in 25 s. The direction of the motion of the body remains unchanged. What is the magnitude and direction of the force?

Answer»

Here, u = 2 ms^-1, v = 3.5 ms^-1, t = 25 s

From v = u + at ⇒ 3.5 = 2 + a x 25

⇒ a = {3.5 - 2}/{25} = 0.06 ms^-2

Mass of the body = m = 3 kg

Force acting on the body

F = ma = 3 x 0.06 = 0.18 N

Since the applied force increases the speed of the body, it acts in the direction of the motion.