A constant force −→F1=(2^i−4^j) N displaces a particle from (1,−1,2) to (−1,−1,3) and then another force −→F2=(3^i+4^j) N displaces it from (−1,−1,3) to (5,5,5) (displacement being measured in metres). Find the total work done.

A constant force −→F1=(2^i−4^j) N displaces a particle from (1,�

1.	A constant force −→F1=(2^i−4^j) N displaces a particle from (1,−1,2) to (−1,−1,3) and then another force −→F2=(3^i+4^j) N displaces it from (−1,−1,3) to (5,5,5) (displacement being measured in metres). Find the total work done.
Answer» A constant force $_{1} = (2^i - 4^j) N$ displaces a particle from $(1, - 1, 2)$ to $(- 1, - 1, 3)$ and then another force $_{2} = (3^i + 4^j) N$ displaces it from $(- 1, - 1, 3)$ to $(5, 5, 5)$ (displacement being measured in metres). Find the total work done.

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A constant force −→F1=(2^i−4^j) N displaces a particle from (1,−1,2) to (−1,−1,3) and then another force −→F2=(3^i+4^j) N displaces it from (−1,−1,3) to (5,5,5) (displacement being measured in metres). Find the total work done.

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